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A particle executing SHM while moving from one extremity is found at distance `x_(1),x_(2)` and `x_(3)` from the center at the end of three successive seconds. The time period of oscillatin is Here `theta=cos^(-1)((x_(1)+x_(3))/(2x_(2))`A. `(2pi)/theta`B. `pi/theta`C. `theta`D. `theta/(2theta)` |
Answer» Correct Answer - A |
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