1.

A particle goes round a circular path with uniform speed v.After describing half the circle, what is the change in its centripetal acceleration?A. `(v^(2))/(r)`B. `(2v^(2))/(r)`C. `(2v^(2))/(pir)`D. `(v^(2))/(pir)`

Answer» Correct Answer - B
`Delta a =2a "sin" (theta)/(2)=(2v^(2))/(r)xx1=(2v^(2))/(r) m//s`.


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