A particle having mass 1 g and electric charge 10^(-8) Ctravels from a point A having electric potential 600 V to the point B having zero potential. What would be the change in its kinetic energy ?

A particle having mass 1 g and electric charge 10^(-8) Ctravels from a

1.	A particle having mass 1 g and electric charge 10^(-8) Ctravels from a point A having electric potential 600 V to the point B having zero potential. What would be the change in its kinetic energy ?
Answer» `-6 xx10^(-6) ` erg `-6 xx10^(-6) `J `6xx10^(-6) ` J `6 xx10^(-6) ` erg Solution :From the definition of ELECTRIC potential, work done by electric field in moving a unit positive charge from POINT A to B = W = 600 J `:. ` Work done in moving `10^(-8)` C charge from point A to B `= 600xx10^(-8) =6xx10^(-6)J` ACCORDING to work energy theorem , `W = Delta :. W = Delta K = 6xx10^(-6)` J

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A particle having mass 1 g and electric charge 10^(-8) Ctravels from a point A having electric potential 600 V to the point B having zero potential. What would be the change in its kinetic energy ?

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