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A particle having rest mass m_(0) travel with speed of light in vaccum.Its de-Broglie wavelength will be….. |
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Answer» `(h)/(m_(0)c)` `lambda=(hxxsqrt(1-(v^(2))/(v^(2))))/(m_(0)v) THEREFORE m=(m_(0))/(sqrt(1-v^(2)/(c^(2))))` `lambda=(hxxsqrt(1-c^(2)/(c^(2))))/(m_(0)v) therefore v=c` `therefore lambda=0` |
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