InterviewSolution
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InterviewSolution
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A particle is dropped from point P at time t = 0. At the same time another particle is thrown from point O as shown in the figure and it collides with the particle P. Acceleration due to gravity is along the negative y-axis. If the two particles collide 2 s after they start, find the initial velocity `v_0` of the particle which was projected from O. Point O is not necessarily on ground. A. `sqrt(6)m//s^(-1),theta=tan^(-1)(1)` with x-axisB. `sqrt(26)m//s^(-10theta=tan^(-1)(5)` with x-axisC. `sqrt(2)m//s^(-1),theta=tan^(-1)(2)` with x-axisD. `sqrt(13)m//s^(-1),theta=tan^(-1)(4)` with axis |
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Answer» Correct Answer - b `x=(u cos theta)t=2, u cos theta=1` `(u sin theta)t-(1)/(2)g t^(2)=-10, u sin theta=5` `v=sqrt((u cos theta)^(2)+(u sin theta)^(2))=sqrt(26), tan theta=5` |
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