InterviewSolution
Saved Bookmarks
| 1. |
A particle is executing a simple harmonic motion its maximum acceleration is a and maximum velocity is `beta` .Then its time of vibration will beA. `(2pialpha)/(beta)`B. `(2pi beta)/(alpha)`C. `2pialphabeta`D. `(pibeta)/(alpha)` |
|
Answer» Correct Answer - A `alpha=A omega` `beta=omega^(2) A ` `T=-(2pi alpha)/(beta)` |
|