1.

A particle is executing a simple harmonic motion its maximum acceleration is a and maximum velocity is `beta` .Then its time of vibration will beA. `(2pialpha)/(beta)`B. `(2pi beta)/(alpha)`C. `2pialphabeta`D. `(pibeta)/(alpha)`

Answer» Correct Answer - A
`alpha=A omega`
`beta=omega^(2) A `
`T=-(2pi alpha)/(beta)`


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