1.

A particle is executing SHM according to the equation `x = A cos omega t`. Average speed of the particle during the interval `0 le t le (pi)/(6omega)` isA. `(sqrt(3)Aomega)/(2)`B. `(sqrt(3) A omega)/(4)`C. `(3Aomega)/(pi)`D. `(3 A omega)/(pi)(2 - sqrt(3))`

Answer» Correct Answer - D
`t = (pi)/(6omega)`
`:. omega t = (pi//6)`
According to the equation, `X = A cos omega t`
`X = A` at `t = 0`
and `X = (sqrt (3) A)/(2)` at `omega t = pi//6`
`:.` Distance travelled
` = A - (sqrt 3)/(2) A`
`= (2 - sqrt3)(A)/(2)`
Average speed `= ("distance")/("time")`
`= ((2 - sqrt3)A//2)/((pi//6omega)) = (3omega A)/(pi) (2 - sqrt3)`.


Discussion

No Comment Found

Related InterviewSolutions