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A particle is executing `SHM`. Find the positions of the particle where its speed is `8 cm//s`, if maximum magnitudes of its velocity and accleration are `10 cm//s` and `50 cm//s` respectively. |
Answer» Correct Answer - `+- (6)/(5) cm = +- 1.2 cm` from the mean position `|v| = |A|omega rArr 10 = |A|omega` `|a| = |A|omega^(2) rArr 50 = |A|omega^(2)` `rArr omega = 5 rArr |A|= 2` `v^(2) = omega^(2)(A^(2) - x^(2))` `8^(2) = 5^(2)(2^(2) - x^(2))` `4 - x^(2) = (64)/(25) rArr x^(2) = (36)/(25) rArr x = +- (6)/(5) cm` |
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