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A particle is executing SHM given by `x = A sin (pit + phi)`. The initial displacement of particle is `1 cm` and its initial velocity is `pi cm//sec`. Find the amplitude of motion and initial phase of the particle. |
Answer» Correct Answer - A::B::C::D `x = A sin (pit + phi)` At `t = 0 , x= 1 cm rArr A sinphi = 1"…."(i)` Velocity `v = (dx)/(dt) = piA cos (pit + phi)` At `t = 0 pi = piA cos phi rarr Acosphi = 1"……."(ii)` from `(i)` & `(ii) A^(2) (sin^(2)phi + cos^(2) phi) = 1 + 1` `rArr A = sqrt(2) cm` and `tanphi = 1 rArr phi = (pi)/(4) rad` |
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