A particle is initially at point `A(2,4,6)m` moves finally to the point` B(3,2,-3)m`. Write the initial position vector,final position,and displacement vector of the particle.

A particle is initially at point `A(2,4,6)m` moves finally to the poin

1.	A particle is initially at point `A(2,4,6)m` moves finally to the point` B(3,2,-3)m`. Write the initial position vector,final position,and displacement vector of the particle.
Answer» Initial position vector : `vec(r )_(1)=2hat(i)+4hat(j)+6hat(k)` Final position vector : `vec(r )_(2)=3hat(i)+2hat(j)-3hat(k)` Displacement : `vec(d)=vec(r )_(2)-vec(r )_(1)=(3-2)hat(i)+(2-4)hat(j)+(-3-6)hat(k)` `=hat(i)-2hat(j)-9hat(k)`

Discussion

No Comment Found

Related InterviewSolutions

When two vectors of magnitudes P and Q are inclined at an angle `theta`, the magnitudes of their resultant is 2P. When the inclination is changed to `180^(@)-theta`, the magnitudes of the resultant is halved. Find the ratio of `P` and `Q`.
If the resultant of two forces of magnitudes `p` and `2p` is perpendicular to `p`, then the angle between the forces isA. `(2pi)/3`B. `(3pi)/4`C. `(4pi)/5`D. `(5pi)/6`
In a methane `(CH_(4)` molecule each hydrogen atom is at a corner of a regular tetrahedron with the carbon atom at the centre. In coordinates where one of the `C-H` bond in the `hat(i)-hat(j)-hat(k)`, an adjacent `C-H` bond in the `hat(i)-hat(j)-hat(k)` direction. Then angle between these two bonds.A. `cos^(-1)(2/3)`B. `cos^(-1)(2/3)`C. `cos^(-1)(-1/3)`D. `cos^(-1)(1/3)`
If `vecA,vecB,vecC` are mutually perpendicular show that `vecCxx(vecAxxvecB)=0`. Is the converse true?
For the any two vecrtors `vecA` and `vecB`, if `vecA.vecB=|vecAxxvecB|`, the magnitude of `vecC=vecA+vecB` is equal toA. `sqrt(A^(2)+B^(2)`B. `A+B`C. `sqrt(A^(2)+B^(2)+(AB)/(sqrt(2)))`D. `sqrt(A^(2)+B^(2)+sqrt(2)xxAB)`
A magnitude of vector `vecA,vecB` and `vecC` are respectively `12, 5` and `13` units and `vecA+vecB=vecC` then the angle between `vecA` and `vecB` isA. `0`B. `pi`C. `pi//2`D. `pi//4`
A magnitude of vector `vecA,vecB` and `vecC` are respectively `12, 5` and `13` units and `vecA+vecB=vecC` then the angle between `vecA` and `vecB` is
If `vecA = vecB + vecC` and the magnitudes of `vecA, vecB and vecC` are 5,4 and 3 units respecetively, the angle between `vecA` and `vecC` is :A. `cos ^(-1)(3//5)`B. `cos ^(-1)(4//5)`C. `pi//2`D. `sin^(-1)(3//4)`
Two vectors `vec A and vecB` have equal magnitudes.If magnitude of `(vecA+vecB)` is equal to n times ofthe magnitude of `(vecA-vecB)` then the anglebetween `vecA and vecB` is :-A. `cos^(-1) ((n - 1)/(n + 1))`B. `cos^(-1) ((n^(2) - 1)/(n^(2) + 1))`C. `sin^(-1) ((n - 1)/(n + 1))`D. `sin^(-1) ((n^(2) - 1)/(n^(2) + 1))`
Consider three vectors `vecA, vecB and vecC` having magnitudes 4, 5, and 3. These vectors are of similar nature, e.g. these could be there displacement. Apply your answer understanding of vectors algebra to match Column-I with Column-II.

A particle is initially at point `A(2,4,6)m` moves finally to the point` B(3,2,-3)m`. Write the initial position vector,final position,and displacement vector of the particle.

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment