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A particle is kept fixed on a turntable rotating uniformly. As seen from the ground the particle goes in a circle, its speed is `20 cm//s` & acceleration is `20 cm//s^(2)`. The particle is now shifted to a new position to make the radius half of the original value. The new values of the speed & acceleration will be:A. `10 cm//s,10 cm//s^(2)`B. `10cm//s,80cm//s^(2)`C. `40 cm//s, 10 cm//s^(2)`D. `40 cm//s,40cm//s^(2)` |
Answer» Correct Answer - A |
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