A particle is launched from a height 8R above the surface of earth and it is given a speed ((GM)/(8R)) parallel to the surfaces then

A particle is launched from a height 8R above the surface of earth and

1.	A particle is launched from a height 8R above the surface of earth and it is given a speed ((GM)/(8R)) parallel to the surfaces then
Answer» It will escape FRO the gravitational field of earth. It will FOLLOW a circular orbit. It will follow an elliptical orbit. the point of launching will be the perigee of its orbit. Solution :Speed is more than the ORBITAL but less than the escape velocity therefore an orbit will form. The speed is perpendicular to the radius. It MUST be either an apogee or a perigee. But since the speed will be INCREASING, the launch point must be the perigee.

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A particle is launched from a height 8R above the surface of earth and it is given a speed ((GM)/(8R)) parallel to the surfaces then

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