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A particle is moving along a circular along a circular path of radius 5 m with a uniform speed `5ms^(-1)`. What will be the average acceleration when the particle completes half revolution?A. ZeroB. `10ms^(-2)`C. `10pims^(-2)`D. `(10)/(pi)ms^(-2)` |
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Answer» Correct Answer - D `a_(av)=(Deltav)/(Deltat)=(2xx5)/(pi)=(10)/(pi)ms^(-2),T=2pi` |
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