1.

A particle is moving along a straight line path according to the relations s^(2)=at^(2)+2bt+c represent the distance travelled in t seconds and a, b, c are constant. Then the acceleration of the particle varies as:

Answer»

`s^(-3)`
`s^(3//2)`
`s^(-2//3)`
`s^(2)`

SOLUTION :Here `s^(2)=at^(2)+2bt+c`
Diff.both sides `2d(ds)/(dt)=2a+2b`
or `v=(ds)/(dt)=(2(at+b))/(2S)=(at+b)/(s)`
`f=([as-(at+b)][at+b])/(s^(3)`
or ` FPROP s^(-3)`


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