InterviewSolution
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InterviewSolution
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A particle is moving along x-axis under the action of force, F which varies with its position as `F prop(1)/(4sqrtx).` Find the variation of power due to this fore with x. |
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Answer» `F propx^(-1//4)` `impliesaprop x^(-1//4)` `impliesa=kx^(-1//4)` (where k is a proporationality constant) `a=(dv)/(dt)=(dx)/(dt)(dv)/(dx)=kx^(-1//4)` `(vdv)/(dx)=kx^(-1//4)` `intvdv=kintx^(-1//4)dx` `(v^(2))/(2)=k(x^(3//4))/(3//4).` `v^(2)propx^(3//4)` `v propx^(3//8)` `thereforeP=Fv` `p prop(x^(3//8))/(x^(1//4))P propx^(1//8)` |
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