InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
A particle is moving along x-axis under the action of a force F, which varies with its position `(x)as fprop(1)/(sqrtx).`Find the variation of power due to this force with x. |
|
Answer» `Fpropx^(-1//2)thereforea=Kx^(-1//2)` `a or (vdv)/(dx)=kx^(-1//2)` ltbr"gt `intvdv=kintx^(-1//2)dx` Find v. `P=Fv` `Pprop(v)/(sqrtx)` `F propx^(1//2)` `a prop^(-1//2)` `a=kx^(-1//2)` (k is a proporationality constant) `(dv)/(dt)=(dx)/(dt)(dv)/(dx)=kx^(-1//2)` `v(dv)/(dx)=kx^(-1//2)` `intvdv=kintx^(-1//2)dx` `(v^(2))/(2)=k(x^(1//2))/(1//2)` `v^(2)propx^(1//2)` `v propx^(1//4)` `P=Fv` `Pprop(x^(1//4))/(sqrt4)` `P propx^(-1//4)` |
|