A particle is moving eastwards with a velocity of ` 5 ms_(-1)`. In `10 seconds` the velocity changes to `5 ms^(-1)` northwards. The average acceleration in this time isA. ZeroB. `1/(sqrt(2))m//s^(2) N-W`C. `1/(sqrt(2))m//s^(2)N-E`D. `1/(sqrt(2))m//s^(2) S-W`

A particle is moving eastwards with a velocity of ` 5 ms_(-1)`. In `10

1.	A particle is moving eastwards with a velocity of ` 5 ms_(-1)`. In `10 seconds` the velocity changes to `5 ms^(-1)` northwards. The average acceleration in this time isA. ZeroB. `1/(sqrt(2))m//s^(2) N-W`C. `1/(sqrt(2))m//s^(2)N-E`D. `1/(sqrt(2))m//s^(2) S-W`
Answer» Correct Answer - B `Deltav= 2v sin ((theta)/(2))= 2xx5xxsin 45^(@)= (10)/(sqrt(2))` `:. a=(Deltav)/(Deltat)= (10sqrt(2))/(10)= 1/(sqrt(2))m//s^(2)`

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A particle is moving eastwards with a velocity of ` 5 ms_(-1)`. In `10 seconds` the velocity changes to `5 ms^(-1)` northwards. The average acceleration in this time isA. ZeroB. `1/(sqrt(2))m//s^(2) N-W`C. `1/(sqrt(2))m//s^(2)N-E`D. `1/(sqrt(2))m//s^(2) S-W`

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