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A particle is moving in a circular path of given radius with (i) constant (ii) increasing (iii) decreasing number of rotations per second. What happens to work done in three cases. |
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Answer» SOLUTION :We know that the work done is equal to the change in KINETIC energy of the SYSTEM. Hence (i) When speed is constant, K.E. does not change so , work done is zero. (ii) When K.E. is increasing, work is done by EXERTING force. (iii) When K.E. is decreasing, work is done by the body on the force. |
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