1.

A particle is moving in a circular path of radius 1 m. under the action of a centripetal force, the speed `sqrt2pi ms^(-1)` of the particle is constant. Find the average of the velocity `("in" ms^(-1))` between A and B.

Answer» Correct Answer - 4
`v_(av) = (rsqrt2)/(T//4) = (rsqrt2xx4v)/(2pir) = (2sqrt2v)/pi = (2sqrt(2)(sqrt2)pi)/pi = 4ms^(-1)`.


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