Two graphs of the same projectile motion (in the xy-plane) projected from origin are shown. X-axis is along horizontal direction and y-axis is vertically upwards. Take `g = 10 ms^(-2)`. Projection angle with the horizontal is :A. `tan^(-1) (4/5)`B. `tan^(-1) (2/3)`C. `tan^(-1) (5/4)`D. `tan^(-1) (1/2)`

Two graphs of the same projectile motion (in the xy-plane) projected f

1.	Two graphs of the same projectile motion (in the xy-plane) projected from origin are shown. X-axis is along horizontal direction and y-axis is vertically upwards. Take `g = 10 ms^(-2)`. Projection angle with the horizontal is :A. `tan^(-1) (4/5)`B. `tan^(-1) (2/3)`C. `tan^(-1) (5/4)`D. `tan^(-1) (1/2)`
Answer» Correct Answer - C Time of flight (T) = 1s `(2u_y)/g = 1s rArr u_y = 5ms^(-1)` Range (R) = 4m. `(2(u_x)(u_y)).g = 4 rArr u_x = 4 ms^(-1)` `u = sqrt(u_x^2 + u_(y)^(2)) = sqrt (41) ms^(-1)` `theta = tan^(-1) (u_y/u_x) = tan^(-1) (5/4)` `H = (u_y^2)/(2g) = (5)^2/20 = 5/4 = 1.25m`.

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