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A particle is moving in a straight line and its distance s cm from a fixed point in the line after t seconds is given by s = 12t – 15t^2 + 4t^3. What is the acceleration of the particle after 3 seconds?(a) 41 cm/sec^2(b) 42 cm/sec^2(c) 43 cm/sec^2(d) 44 cm/sec^2I got this question in an internship interview.The origin of the question is Calculus Application in portion Application of Calculus of Mathematics – Class 12 |
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Answer» The CORRECT OPTION is (B) 42 cm/sec^2 |
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