1.

A particle is moving in a straight line and its distance s cm from a fixed point in the line after t seconds is given by s = 12t – 15t^2 + 4t^3. What is the velocity of the particle after 3 seconds?(a) 10 cm/sec(b) 20 cm/sec(c) 30 cm/sec(d) 40 cm/secThe question was asked in class test.I want to ask this question from Calculus Application topic in section Application of Calculus of Mathematics – Class 12

Answer»

Correct option is (c) 30 cm/sec

To ELABORATE: We have, s = 12T – 15t^2 + 4t^3 ……….(1)

Differentiating both SIDE of (1) with respect to t we get,

(ds/dt) = 12 – 30t + 12t^2

So, VELOCITY of the particle after 3 seconds is,

[ds/dt]t = 3 = 12 – 30(3) + 12(3)^2

= 30 cm/sec.



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