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A particle is moving in a straight line is at a distance x from a fixed point in the straight line at time t seconds, where x = 2t^3 – 12t + 11. What is the displacement of the particle at the end of 2 seconds?(a) 1 cm(b) 2 cm(c) 3 cm(d) 4 cmI got this question in an online interview.This question is from Calculus Application topic in section Application of Calculus of Mathematics – Class 12

Answer»

The correct choice is (c) 3 CM

Easy EXPLANATION: We have, X = 2t^3 – 12t + 11 ……….(1)

Putting t = 2 in (1), we get,

Displacement = x = 2t^3 – 12t + 11

= 2(2)^3 – 12(2) + 11

= 3 cm.



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