A particle is moving in such a way that its velocity versus time graph is a parabola (t=kv^(2),k is constant) as shown in the figure. Choose the correct option(s)

A particle is moving in such a way that its velocity versus time graph

1.	A particle is moving in such a way that its velocity versus time graph is a parabola (t=kv^(2),k is constant) as shown in the figure. Choose the correct option(s)
Answer» ACCELERATION of the particle is `sqrt(3)m//s^(2)` throughout the journey average acceleration of particle is `1m//s^(2)` for the INTERVAL of first 5 sec average acceleration of particle is LESS than `sqrt(3)m//s^(2)` for the interval of first 5 sec average acceleration of particle is less than `1m//s^(2)` for the interval of 5 sec to 10 sec Solution :AVG. acceleration `=("change in velocity")/("TIME interval")`

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A particle is moving in such a way that its velocity versus time graph is a parabola (t=kv^(2),k is constant) as shown in the figure. Choose the correct option(s)

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