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A particle is moving three times as fast as an electron. The ratio of the de Broglie wavelength of the particle to that of the electron is 1.813xx10^(-4). Calculate the particle's mass and identifythe particle. |
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Answer» Solution :de Broglie wavelength of a moving particle, having MASS m and velocity v : `lambda=(h)/(p)=(h)/(mv)` Mass, `m=h//lambda v` For an electron, mass `=h//lambda_(e ) v_(e )` Now, we have `m_(e )v//v_(e )=3` and `lambda/lambda_(e )=1.813xx10^(-4)` Then, mass of the particle, `m= me((lambda_(e ))/(lambda))((upsilon_(e ))/(UPSILON))` `m=(9.11xx10^(-31)KG)xx(1//3)xx(1//1.813xx10^(-4))` `m=1.675xx10^(-27)kg`. Thus, the particle, with this mass COULD be a proton or a NEUTRON. |
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