InterviewSolution
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InterviewSolution
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A particle is moving with constant speed v along x-axis in positive direction. Find the angularvelocity of the particle about the point (0, b), when position of the particle is (a, 0). |
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Answer» namanpreet bhai plz bta dena ye shi h ya galat plz W=v(perpendicular)/r ( where r is the distance between the position of the particle and the point about which the angular velocity is to be calculated) thus,W=vcos/r {m using '' for theta} From the triangle ABC,sin=b/root of (a^2+b^2) where = 90-, Thus sin(90-)= cos, Therefore, cos=b/root of (a^2+b^2). So,W={v*b/root of (a^2+b^2)}/root of(a^2+b^2). which is equal to vb/a^2+b^2. Thus angular velocity = vb/a^2+b^2. shi h bhai shukriya bhai apka |
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