1.

A particle is moving with velocity 5 m/s towards cast and its velocity changes to 5 m/s north in 10 s, find the acceleration .

Answer»

`sqrt(2) ` North- West
`(1)/(sqrt(2))` North - West
`(1)/(sqrt(2))` North - East
`sqrt(2)` North -East

Solution :In the GIVEN figure, change in velocity in 10 s is stance travelled by the body. represented by diagonal oT of parallclogram OBTC where
`OT = sqrt(5^(2)+5^(2))= 5sqrt(2)`
Acceleration = `("Change in velocity" )/("TIME TAKEN ")`
`(5sqrt(2))/(10)= (1)/(sqrt(2))m//s^(2)` (North -west )


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