1.

A particle is moving with velocity vec(v)=K(yhati + xhatj), where K is a constant. The general equation for its path is:

Answer»

`y^(2)=X^(2)` + constant
`y=x^(2)` + constant
`y^(2) = x + ` constant
xy =constant

Solution :GIVEN `(dx)/(dt)HATI+(DY)/(dt)hatj=K(yhati+xhatj)`

`:.dx/dt=Ky` and `(dy)/(dt)=Kx`
`implies dx/dt=y/x` and xdx=ydv or integrating `x^(2)=y^(2)+c`


Discussion

No Comment Found

Related InterviewSolutions