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A particle is performing a linear simple harmonic motion. If the instantaneous acceleration and velocity of the particle are `a` and `v` respectively, identify the graph which correctly represents the relation between `a` and `v`.A. B. C. D. |
Answer» Correct Answer - C If `v = v_(0)sin omega t`, then `a = (dv)/(dt) = v_(0) omega cos omega t` `sin omega t = (v)/(v_(0))` …(i) `cos omega t = (a)/(v_(0)omega)` …(ii) Squaring and adding these equations, we get `1 = (v_(2))/(v_(0)^(2) + (a^(2))/(v_(0)omega)` `:. v^(2) = (-(v_(0))/(omega)) a^(2) + v_(0)^(2)` Hence, `v^(2)` versus `a^(2)` equation is a straight line with positive intercept and negative slope. |
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