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A particle is performing S.H.M. Its total energy ie E When the displacement of the particle is half of its amplitude, its K.E. will beA. E/2B. E/4C. 3E/4D. E/8 |
Answer» Correct Answer - B (b) `U=(1)/(2)momega^(2)x^(2)=(1)/(2)momega^(2)((A^(2))/(4))=(1)/(4)E` |
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