A particle is placed at the origin and a force F = kx is acting on it (where k is a positive constant). If U (0) = 0, the graph of U (x) versus x will be (where U is the potential energy function) :

A particle is placed at the origin and a force F = kx is acting on it

1.	A particle is placed at the origin and a force F = kx is acting on it (where k is a positive constant). If U (0) = 0, the graph of U (x) versus x will be (where U is the potential energy function) :
Answer» Solution :Since F =`-(dU)/(dx)=kx` `thereforedU=-Kxdx` or `U=-Kxdx=-1/2Kx^(2)` This is QUADRATIC equation i.e., equation of a PARABOLA. THUS correct choice is (a).

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A particle is placed at the origin and a force F = kx is acting on it (where k is a positive constant). If U (0) = 0, the graph of U (x) versus x will be (where U is the potential energy function) :

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