1.

A particle is projected at an angle of 45° from the foot of a wall, just touches the top of the wall and falls on the ground on the opposite sides at a distance 4 m from it. The height of wall is :

Answer»

`2/3m`
`4/3m`
`8/3m`
`3/4m`

SOLUTION :Here `theta=45^@` and `U^(2)/g=6` or `u^(2)=6g`, also
`ucostheta,t=2,OR2/(ucostheta)` and y=height of wall, then
`y=usintheta,t+1/2g t^(2)`
`usinthetaxx2/(ucostheta)+1/2gxx4/(u^(2)cos^(2)theta)` or `y=8/3`m


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