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A particle is projected at an angle of 45° from the foot of a wall, just touches the top of the wall and falls on the ground on the opposite sides at a distance 4 m from it. The height of wall is : |
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Answer» `2/3m` `ucostheta,t=2,OR2/(ucostheta)` and y=height of wall, then `y=usintheta,t+1/2g t^(2)` `usinthetaxx2/(ucostheta)+1/2gxx4/(u^(2)cos^(2)theta)` or `y=8/3`m |
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