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A particle is projected from a tower as shown in figure, then find the distance from the foor of the tower where it will strike the ground (g=10 m//s^(2)) |
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Answer» Solution :`s=ut+(1)/(2) at^(2)` `1500=(500)/(3)XX(3)/(5)t+5t^(2) RARR 300= 20t+t^(2)` On solving t=10 s `:.` Horizontal distance `= U cos theta. T` `=(500)/(3) xx(4)/(5) xx10=(4000)/(3) m` 
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