A particle is projected from point P on inclined plane OA perpendicular to it with certain velocity v. It this another inclined plane OB at point Q perpendicular to it. Point P and Q are at h_(1) and h_(2) height from ground. (alpha gt beta)

A particle is projected from point P on inclined plane OA perpendicula

1.	A particle is projected from point P on inclined plane OA perpendicular to it with certain velocity v. It this another inclined plane OB at point Q perpendicular to it. Point P and Q are at h_(1) and h_(2) height from ground. (alpha gt beta)
Answer» `h_(1)=h_(2)` `h_(1) gt h_(2)` `h_(1) lt h_(2)` any of above depends on SPEED of projection. Solution :PERPENDICULAR to `OB`, `v'=-vsintheta(90^(@)-alpha-beta)+g cos beta t`…..(`i`) Parallel to `OB`, `0=v cos(90^(@)-alpha-beta)-g sin beta t`……(`ii`) on SOLVING `v'=(vsin alpha)/(sinbeta)` for `alpha gt beta`, `v' gt v`, so by ENERGY conservation `h_(2) lt h_(1)`

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A particle is projected from point P on inclined plane OA perpendicular to it with certain velocity v. It this another inclined plane OB at point Q perpendicular to it. Point P and Q are at h_(1) and h_(2) height from ground. (alpha gt beta)

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