1.

A particle is projected from the ground so as to graze the four upper vertices of a regular hexagor, whose side is 2a and which is placed vertically with one side on the ground. What is the ratio of the velocity of the particle on reaching the ground to the least velocity?

Answer»

`SQRT((31)/(3))`
`sqrt((34)/(3))`
`sqrt((16)/(3))`
`sqrt((7)/(3))`

Solution :`R=2asqrt(7)=U_(x)xx(2U_(y))/(g)`
Ratio `=sqrt(U_(x)^(2)+U_(y)^(2))/(U_(x))=sqrt(1+((U_(y))/(U_(x)))^(2))`
`=sqrt(1+tan^(2)theta)`


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