1.

A particle is projected from the ground with an initial speed of v at an angle of projection theta. The average velocity of the particle between its time of projection and time it reaches highest point of trajectory is (2013 E)

Answer»

`(v)/(2)sqrt(1+2cos^(2)THETA)`
`(v)/(2)sqrt(1+2sin^(2)theta)`
`(v)/(2)sqrt(1+3cos^(2)theta)`
`vcostheta`

ANSWER :C


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