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A particle is projected with a speed u at angle `theta` with the horizontal. Consider a small part of its path ner the highest position and take it approximately to be a circular arc. What is the rdius of this circle? This radius is called the adius of curvature of the curve at the point. |
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Answer» Correct Answer - A::B::C Particle is projected with speed u at an angle `theta`. At the highest point the veticasl component of velocity is 0. So at the point, velocity`=ucostheta` Centripetal force `=(mu^2cos^2theta)/r` At highest point `mg=(mv^2)/r=(mu^2 cos^2theta)/r` `rarr r=(u^2cos^2theta)/g` |
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