A particle is subjecte to two simple harmonic motions gilven by `x_1=2.0sin(100pit_)and x_2=2.0sin(120pi+pi/3)`, where x is in centimeter and t in second. Find the displacement of the particle at a. t=0.0125, b. t= 0.025.

A particle is subjecte to two simple harmonic motions gilven by `x_1=2

1.	A particle is subjecte to two simple harmonic motions gilven by `x_1=2.0sin(100pit_)and x_2=2.0sin(120pi+pi/3)`, where x is in centimeter and t in second. Find the displacement of the particle at a. t=0.0125, b. t= 0.025.
Answer» Correct Answer - A::B::C::D `x_1=2sin100pit` `x_2=2sin(120pit+pi/3)` so, resultant displacement is given by `x=x_1+x_2` `=[sin(100pit)+sin(120pit+pi/3)]` a. At t=0.0125s `x=2[(sin(100pix0.0125+sin(120ixx0.0125+pi/3))]` `=2[sin(5pi)/4+sin((3pi)/2)+pi/3]` `=2[(-0.707)+(-0.5)]` `=2xx(-1.207)=-2.41cm` b. At t=0.025s `x=2[(sin(100pixx0.025)+sin(120pixx0.025+pi/3)]` `=2[sin((10pi)/4)+sin(3pi+pi/3)]` `=2[1+(-0.866)]` `=2xx(0.134)=0.27cm`

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A particle is subjecte to two simple harmonic motions gilven by `x_1=2.0sin(100pit_)and x_2=2.0sin(120pi+pi/3)`, where x is in centimeter and t in second. Find the displacement of the particle at a. t=0.0125, b. t= 0.025.

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