InterviewSolution
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InterviewSolution
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A particle is thrown up verticaly with a velocity with a velocity of `50 m//s`. what will be its velocity at the highest point of the journey ? How high would the particle rise ? What time would it take it take to reach the highest point ? Take `g=10m//s^(2)`. |
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Answer» Here, intial velocity, `u=50m//s`, final velocity, `v=?` height coverd, `h=?` time taken, `t=?` `g=10m//s^(2)` At the highest point, final velocity `v=0`. From `v^(2)-u^(2)=2gh`, where `g=-10m//s^(2)` for upward journey, `0-(50)^(2)=(-10)h` or `h=-(2500)/(-20)=125m` `v=u+g t, 0=50+(-10)t` or `t=50//10=5s` |
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