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A particle is thrown vertically up with a velocity of 50 m/s. what will be its velocity at highestpoint of journey? How high would the particle rise? What time it takes to reach the highest point?Take the value of g-10 m/ s) |
Answer» <p>U= 50m/sg= -10m/s^2</p><p>The velocity at the highest point will be 0 m/sThus v=0</p><p>Height can be calculated by</p><p>2gs=v^2-u^2-20s= -2500s= 125m</p><p>Time :v= u+gt0=50-10t-50=-10tt= 5sec</p><p>Like my answer if you find it useful!</p> | |