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A particle is throws vertically upwards from the surface of earth and it reaches to a maximum height equal to the radius of earth. The radio of the velocity of projection to the escape velocity on the surface of earth isA. `(1)/(sqrt2)`B. `(1)/(2)`C. `(1)/(4)`D. `(1)/(2sqrt2)` |
Answer» Correct Answer - A Change in kinetic energy = change in potential energy `:. (1)/(2) m nu^(2) = - (GMm)/(R + R) - (-(GMm)/(R))` `t((GM)/(R)) = sqrt(2GM//R)/(sqrt(2))` `= (nu_(e))/(sqrt(2))` where, `nu_(e) =` escape velocity |
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