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A particle is travelling along a straight line OX. The distance r of the particle from O at a timet is given by x = 37 + 27t- t^(3), where t is time in seconds. The distance of the particle from O when it comes to rest is |
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Answer» 81 m VELOCITY `nu=(DX)/(dt) =(d)/(dt) (37+27t-t^(3))` `=27-3t^(2)` It come to REST `nu=0` `:. 27-3t^(2)=0 "or " 3t^(2) = 27` or `t^(2) = (27)/(3) =9 ` or t=3 s At t=3 s , `x=37+27(3) -(3)^(3) = 37 +81 -27 =91 ` m |
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