A particle leaves the origin with an initial velocityo-3/m/s and a con

1.	A particle leaves the origin with an initial velocityo-3/m/s and a constant acceleration39.2 m/s. Its speed when its xcoordinate of position is maximumis 11(1) 3 ms(3) 6 m/s(4) 9 ms
Answer» Well, first we want to find the time in which the particle changes from a positive X speed, to a negative x speed, so we're looking for where x = 0. If we use V = V0+at using initial velocity and acceleration, we get:0 = 3 + -1(t)t = 3 So, it changes direction along the x axis at 0, and that's it's max x. To find velocity, we use time and it's acceleration along the y axis, so...V = V0+atV = 0+.5(3)V = 1.5 = Answer (a)Hence, option (2) is correct.

A particle leaves the origin with an initial velocityo-3/m/s and a constant acceleration39.2 m/s. Its speed when its xcoordinate of position is maximumis 11(1) 3 ms(3) 6 m/s(4) 9 ms

Answer»

Well, first we want to find the time in which the particle changes from a positive X speed, to a negative x speed, so we're looking for where x = 0.

If we use V = V0+at using initial velocity and acceleration, we get:0 = 3 + -1(t)t = 3

So, it changes direction along the x axis at 0, and that's it's max x. To find velocity, we use time and it's acceleration along the y axis, so...V = V0+atV = 0+.5(3)V = 1.5 = Answer (a)Hence, option (2) is correct.

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A particle leaves the origin with an initial velocityo-3/m/s and a constant acceleration39.2 m/s. Its speed when its xcoordinate of position is maximumis 11(1) 3 ms(3) 6 m/s(4) 9 ms

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