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A particle moved from position `vec r_(1) = 3 hati + 2 hatj - 6 hatk `to position`vecr_(2) = 14 hati + 13 hatj +9 hatk` undre the action of a force `(4 hati + hatj +3 hatk)` newtons . Find the work done .A. `10J`B. `100 J`C. `0.01 J`D. `1J` |
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Answer» Correct Answer - B displacement : `vec s = vec r_(2) - vec r_(1)`. Now find `W = vec F. vecs` |
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