A particle moves along a circle of radius R =1m so that its radius vector `vecr` relative to a point on its circumference rotates with the constant angular velocity `omega=2rad//s`. The linear speed of the particle isA. `4m//s`B. `2m//s`C. `1m//s`D. `0.5m//s`

A particle moves along a circle of radius R =1m so that its radius vec

1.	A particle moves along a circle of radius R =1m so that its radius vector `vecr` relative to a point on its circumference rotates with the constant angular velocity `omega=2rad//s`. The linear speed of the particle isA. `4m//s`B. `2m//s`C. `1m//s`D. `0.5m//s`
Answer» Correct Answer - a Angular velocity about centre =2 (angular velocity about any point on its circumference) or `omega=2(2)rad//s` or `omega=4 rad//s` Now `v=romega=(1)(4)=4m//s`

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A particle moves along a circle of radius R =1m so that its radius vector `vecr` relative to a point on its circumference rotates with the constant angular velocity `omega=2rad//s`. The linear speed of the particle isA. `4m//s`B. `2m//s`C. `1m//s`D. `0.5m//s`

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