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A particle moves along a straight line AB. At a time t (in seconds) the distance x (in metres) of the particle from O is given by x = 600 + 12t – `t^3`. How long would the particle travel before coming to rest: -A. 24mB. 40mC. 56mD. 16m |
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Answer» Correct Answer - D `X=40+12t-t^(3)impliesv(dx)/(dt)=12-3t^(2)` `impliesv=0` at t=2sec Distance travelled by particle before coming to rest ltbrgex(at t=2)-x(at t=0)ltbrge`[40+12xx2-2^(3)]-[40]=16m` |
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