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A particle moves along the positive branch of the curve `y = (x^(2))/(2)` where `x = (t^(2))/(2),x` and y are measured in metres and t in second. At `t = 2s`, the velocity of the particle isA. `2hati-4hatj`B. `4hati-2hatj`C. `4hati+2hatj`D. `2hati+4hatj` |
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Answer» Correct Answer - d `v_(x)=(dx)/(dt)+v_(y)=(dy)/(dt)` `vecv=v_(x)hati+v_(y)hatj` |
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