A particle moves along the x - axis according to `x = A[1 + sin omega t]`. What distance does is travel in time interval from `t = 0` to `t = 2.5pi//omega` ?A. `4A`B. `6 A`C. `5 A`D. `3 A`

A particle moves along the x - axis according to `x = A[1 + sin omega

1.	A particle moves along the x - axis according to `x = A[1 + sin omega t]`. What distance does is travel in time interval from `t = 0` to `t = 2.5pi//omega` ?A. `4A`B. `6 A`C. `5 A`D. `3 A`
Answer» Correct Answer - C `t = (2.5 pi)/(omega) = (2.5 pi)/(2pi//T)` `= (2.5)((T)/(2))` `= 5((T)/(4))` Particle starts from extreme position and in every `(T)/(4)` time it travels a distance `A`. So, in time `t = 5(T//4)` it will travel a distance `5A`.

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A particle moves along the x - axis according to `x = A[1 + sin omega t]`. What distance does is travel in time interval from `t = 0` to `t = 2.5pi//omega` ?A. `4A`B. `6 A`C. `5 A`D. `3 A`

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