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A particle moves in a circle of radius 25 cm at two revolutions per sec. The acceleration of the particle in `m//s^(2)` is:A. `pi^(2)`B. `8pi^(2)`C. `4pi^(2)`D. `2pi^(2)` |
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Answer» Correct Answer - c `r=25xx10^(-2)m, f= 2//sec` `omega=2pif=4pi rad//sec` Acceleration `=ometa^(2)r=(4pi)^(2)xx25xx10^(-2)` `=16xx25xx10^(-2)pi^(2)m//s^(2)` `=4pi^(2)m//s^(2)` |
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