A particle moves in a circle with a uniform speed. When it goes from a point A to a diametrically opposite point B, the momentum of the particle changes by vecP_(A)-vecP_(B)=2 kg m/s (hatj) and the centripetal force acting on it changes by vecF_(A)-vecF_(B)=8N(hati) where hati,hatj are unit vectors along X and Y axes respectively. The angular velocity of the particle is

A particle moves in a circle with a uniform speed. When it goes from a

1.	A particle moves in a circle with a uniform speed. When it goes from a point A to a diametrically opposite point B, the momentum of the particle changes by vecP_(A)-vecP_(B)=2 kg m/s (hatj) and the centripetal force acting on it changes by vecF_(A)-vecF_(B)=8N(hati) where hati,hatj are unit vectors along X and Y axes respectively. The angular velocity of the particle is
Answer» `"8 RAD s"^(-1)` `"4 rad s"^(-1)` `"2 rad s"^(-1)` `"16 rad s"^(-1)` Answer :B

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